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Jogos do BlocklyQuebra-Cabe\u00e7aLabirintoP\u00e1ssaroTartarugaFilmeM\u00fasicaTutor de LagoaLagoaGen\u00e9ticasVoc\u00ea solucionou esse n\u00edvel com uma linha de JavaScript:Voc\u00ea solucionou esse n\u00edvel com %1 linhas de JavaScript:Voc\u00ea esta preparado para o n\u00edvel %1?Voc\u00ea esta preparado para o pr\u00f3ximo desafio?T\u00edtulo:Salvar e ligar aos blocos.Rodar o programa que voc\u00ea escreveu.Executar o programaParar a execu\u00e7\u00e3o do programa e resetar o nivel.ReiniciarAjudaOKCancelarL\u00f3gicaLa\u00e7osMatem\u00e1ticaTextoListasCorVari\u00e1veisFun\u00e7\u00f5esHouve um problema com a requisi\u00e7\u00e3o.Compartilhe seus blocos com este link:\n\n%1Desculpe, \'%1\' n\u00e3o corresponde a um programa salvo.N\u00e3o foi poss\u00edvel carregar seu arquivo salvo. Talvez ele tenha sido criado com uma vers\u00e3o diferente do Blockly?Agradecemos pelo programa! Se a nossa equipa gostar dele, este ser\u00e1 publicado na galeria por n\u00f3s dentro de alguns dias.listatextoQuando voc\u00ea come\u00e7ar a editar o JavaScript, voc\u00ea n\u00e3o poder\u00e1 mais voltar a editar os blocos. Voc\u00ea tem certeza?Blocos
Busque inimigos. Especifique uma dire\u00e7\u00e3o(0-360). \\nRetorna a distancia do inimigo mais proximo \\nnaquela dire\u00e7\u00e3o. Retorna infinito se nenhum \\ninimigo for encontrado. Dispare o canh\u00e3o. Especifique uma dire\u00e7\u00e3o \\n(0-360) e o alcance (0-70). Nadar para a frente. Especifique uma dire\u00e7\u00e3o \\n(0-360). Parar de nadar. O jogador fara uma parada lenta. Retorna a saude atual do jogador (0 esta morto, \\n100 esta saud\u00e1vel). Retorna a velocidade atual do jogador (0 esta \\npar\u00e1do, 100 esta na velocidade maxima) Retorna a coordenada X do jogador (0 \u00e9 a margem \\nesquerda, 100 \u00e9 a margem direita). Retorna a coordenada Y do jogador (0 \u00e9 a borda \\ninferior, 100 \u00e9 a borda superior).
JogadorAlvoPenduloAssustado

'+ ((Kc?'':'')+"Jogos do Blockly : "+Z({appName:"Tutor de Lagoa"}.appName)+""),d="   ",e=1;11>e;e++)d+=" "+(e==R?''+Z(e)+"":10==e?''+Z(e)+"":'');a=c+d+'

  
'; switch(R){case 1:case 3:case 5:case 7:case 9:a+='
';break;case 2:case 4:case 6:case 8:case 10:a+='
'}return a+='\n\n\n\n\n\n
Parab\u00e9ns!
'+
(df()+"
")+(5==R||6==R?'
Sua solu\u00e7\u00e3o funciona, mas voc\u00ea pode fazer melhor. Use \'scan\' para mostrar ao canh\u00e3o o qu\u00e3o longe atirar.
'+df()+"
":"")+'
'+(1==R||2==R?"Use o comando 'cannon' para atingir o alvo. O primeiro par\u00e2metro \u00e9 o \u00e2ngulo, o segundo \u00e9 o alcance. Ache a combina\u00e7\u00e3o correta."+
(1==R?'

0\u00b070cannon(,);':
2==R?"
cannon(0, 70);
":""):3==R||4==R?"Este alvo deve ser acertado v\u00e1rias vezes. Use o ciclo 'while (true)' para fazer algo indefinidamente."+(3==R?'

while () {}true \u25be':
4==R?"
while (true) {\n  ...\n}
":""):5==R||6==R?"Esse oponente move-se para frente e para tr\u00e1s, fazendo ficar dif\u00edcil acert\u00e1-lo. A Express\u00e3o 'scan' retorna o alcance exato do oponente naquela dire\u00e7\u00e3o."+(5==R?'

0\u00b0scan()

':
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scan(0)
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0\u00b0swim();':
8==R?"
swim(0);
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< \u25be50getX()

stop();':
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getX() < 50
stop();
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"+df()+"
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